使用 vue3 + element plus 完成动态行列和数据渲染,包括二级分类表格
问题描述
如何使用 vue3 + element plus 开发复杂的表格,其中横向和纵向列都动态生成,数据含有二级分类,并需要合并单元格?
解决方案
html 代码:
<el-table :span-method="arrayspanmethod" :data="tabledata"> <el-table-column label="派出组" align="center" prop="group"></el-table-column> <el-table-column label="累计生产单" align="center" prop="total"></el-table-column> <el-table-column label="案件主办" align="center" prop="person"></el-table-column> <el-table-column v-for="(item, index) in headerlist" :key="index" :label="item.label" align="center" :prop="item.prop"> <el-table-column v-for="(list, i) in item.sublist" :key="i" :label="list.label" align="center" :prop="list.prop"> <template #default="scope">{{ scope.row[item.prop][list.prop] }}</template> </el-table-column> </el-table-column> </el-table>
js 代码:
// 模拟后台返回的表格头部信息 const headerList = ref([ { label: '达飞', prop: 'column1', subList: [ { label: '保理当日', prop: 'day' }, { label: '保理累计', prop: 'total' } ] }, { label: '农行', prop: 'column2', subList: [ { label: '农行秦分当日', prop: 'day' }, { label: '农行秦分累计', prop: 'total' } ] } ]) // 模拟后台返回的表格数据信息 const tableData1 = ref([ { group: '海港组', total: 123, person: 'aa', column1: { day: '500', total: 3000 }, column2: { day: 100, total: 3000 } }, { group: '海港组', total: 123, person: 'bb', column1: { day: '500', total: 3000 }, column2: { day: 100, total: 3000 } }, { group: '海港组', total: 123, person: 'cc', column1: { day: '500', total: 3000 }, column2: { day: 100, total: 3000 } }, { group: '其他组', total: 123, person: 'cc', column1: { day: '500', total: 3000 }, column2: { day: 100, total: 3000 } }, { group: '其他组', total: 123, person: 'cc', column1: { day: '500', total: 3000 }, column2: { day: 100, total: 3000 } }, { group: '其他组', total: 234, person: 'cc', column1: { day: '500', total: 3000 }, column2: { day: 100, total: 3000 } } ]) const groupArr = ref([]) // 用于合并组 const groupPos = ref(0) // 合并行数默认值 const totalArr = ref([]) // 用于合并生产单 const totalPos = ref(0) // 合并生产单默认值 // 表格行合并方法 const merge = (tableData) => { // 要合并的数组的方法 groupArr.value = [] groupPos.value = 0 totalArr.value = [] totalPos.value = 0 for (var i = 0; i < tableData.length; i++) { if (i === 0) { // 第一行必须存在 groupArr.value.push(1) groupPos.value = 0 totalArr.value.push(1) totalPos.value = 0 } else { // 判断当前元素与上一个元素是否相同 this.groupPos是groupArr内容的序号 if (tableData[i].group === tableData[i - 1].group) { groupArr.value[groupPos.value] += 1 groupArr.value.push(0) } else { groupArr.value.push(1) groupPos.value = i } // 生产单合并 if ( tableData[i].total === tableData[i - 1].total && tableData[i].group === tableData[i - 1].group ) { totalArr.value[totalPos.value] += 1 totalArr.value.push(0) } else { totalArr.value.push(1) totalPos.value = i } } } } // 合并行 const arraySpanMethod = ({ row, column, rowIndex, columnIndex }) => { if (columnIndex === 0) { // 合并组 const _row_1 = groupArr.value[rowIndex] const _col_1 = _row_1 > 0 ? 1 : 0 // 如果被合并了_row=0则它这个列需要取消 return { rowspan: _row_1, colspan: _col_1 } } else if (columnIndex === 1) { // 第二列的合并方法,合并生产单 const _row_2 = totalArr.value[rowIndex] const _col_2 = _row_2 > 0 ? 1 : 0 return { rowspan: _row_2, colspan: _col_2 } } } merge(tableData.value)