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Jackson Redis序列化:为什么启用USE_LONG_FOR_INTS后整数仍被反序列化为Integer?

482 2025-03-26

Jackson Redis序列化:为什么启用USE_LONG_FOR_INTS后整数仍被反序列化为Integer?

jackson redis序列化器中启用use_long_for_ints无响应

尽管启用了jackson的use_long_for_ints配置,但整数值仍被反序列化为integer,而不是long。

原因分析

源码显示,反序列化过程调用了untypedobjectdeserializer函数,它未检查use_long_for_ints选项,而是仅检查use_big_integer_for_ints。

解决方案

您可以创建自定义反序列化器,在反序列化时将整数值转换为long:

public class customdeserializer extends jsondeserializer<object> {
    private final untypedobjectdeserializer delegate;

    public customdeserializer() {
        this.delegate = new untypedobjectdeserializer(null, null);
    }

    @override
    public object deserialize(jsonparser p, deserializationcontext ctxt) throws ioexception {
        object value = delegate.deserialize(p, ctxt);
        if (value instanceof integer) {
            return ((integer) value).longvalue();
        }
        return value;
    }
}

然后将自定义反序列化器添加到jackson配置中:

@Bean
@SuppressWarnings("all")
public RedisTemplate<String, Object> redisTemplate(RedisConnectionFactory connectionFactory) {
    RedisTemplate<String, Object> template = new RedisTemplate<>();
    template.setConnectionFactory(connectionFactory);

    ObjectMapper objectMapper = new ObjectMapper();
    objectMapper.registerModule(new SimpleModule().addDeserializer(Object.class, new CustomDeserializer()));

    Jackson2JsonRedisSerializer<Object> jackson2JsonRedisSerializer = new Jackson2JsonRedisSerializer<>(Object.class);
    jackson2JsonRedisSerializer.setObjectMapper(objectMapper);

    template.setKeySerializer(RedisSerializer.string());
    template.setHashKeySerializer(RedisSerializer.string());

    template.setDefaultSerializer(jackson2JsonRedisSerializer);

    return template;
}
来源:1732790619